The count method returns the number of occurrences of the substring of a string.
string.count(substring, startIndex, endIndex)
substring: The substring to be searched on the string.
startIndex: The index from which the substring is to be searched. It is an optional value, and by default the value is 0.
endIndex: The index to which the substring is to be searched. It is an optional value, and by default the value is string.length.
The return value is the number of non-overlapping occurrences of the substring in a string.
string = "educative";print("Number of 'e' in the string ", string)print(string.count('e'))string = "iii"print("\nNumber of 'ii' in the string ", string)print(string.count('ii'))string = "educative"print("\nNumber of 'e' in the string ", string, "from index 1 is")print( string.count('e', 1) ) # this will search for 'e' from index 1 to end of the stringstring = "educative"print("\nNumber of 'e' in the string ", string, "between index 1 and 3 is")print( string.count('e', 1, 3) ) # this will search for 'e' from index 1 to 3rd index of the strinf
In the above code, we:
Created an educative string and used the count method to check how many e are present in the string. The count method will return 2.
Created an iii string and used the count method to check how many ii are present in the string. The count method will return 1 because in the iii string, the first two ii characters match the substring, so the next search will happen from index 2. The search of the substring will take place in a non-overlapping manner.
Created a string educative and checked how many e are present in the string from the index 1 using the count method. The count method will return 1.
Created an educative string and used the count method to check how many e are present in the string between the index 1 and 3. The count method will return 0 because no e is present between the index 1 - 3.