The **`new`** function in Golang allocates memory but does not initialize it as the `make` function does. `new` returns a pointer to the newly allocated zeroed value of type `T`.

# Prototype
```Go
func new(Type) *Type
```
# Parameters
* `Type`: The type of data for which the memory will be allocated.
# Return type
`new()` returns a pointer of type `T`.
# Code

package main
import "fmt"

func main() {
  var a *int
  var b *bool
  var s *string
  var arr *[10]int 

  a = new(int)
  b = new(bool)
  s = new(string)
  arr = new([10]int)

  fmt.Println(a, " ", *a)
  fmt.Println(s,  " ",*s)
  fmt.Println(b,  " ",*b)
  fmt.Println(arr, " ", *arr)
}

In the code above, we declare pointers of types `int`, `bool`, and `string`, and a pointer to an `int` array of `a`, `b`, `s`, and `arr` respectively. 

Then, we allocate memory for each of these pointers and print the values of the pointers and the data pointed to by the pointers. 

What is the Golang function new(Type) *Type?

The new function in Golang allocates zeroed memory for a type and returns a pointer to it.