The **FizzBuzz** problem is a frequently asked question in technical interviews. In real life, it is a game which is played by a group of people. The rules are quite straightforward. 

# The Rules: 

* The sequence of turns is decided before starting the game. 
* The first player starts by saying any number (usually the number 1). 
* The next player says the next number, and so on. However, the following is the tricky part:
   1. Say the word **Fizz** instead of the number when it is a multiple of 3.
   2. Say **Buzz** if it is a multiple of 5.
   3. Say **FizzBuzz** if it is a multiple of both 3 and 5.

* The rules to say these words can be changed. For example, saying **FizzBuzz** when a number is a multiple of both 7 and 9.

If you say the wrong number or word, you're out! The last player standing wins the game.

# Implementing FizzBuzz in Java
 
In Java, this problem is not about playing the game. It is a matter of knowing how to use the if-else condition (or its alternatives) to print (output) the correct number or word. Below is the code using both if-else and the '**?**' operator:

public class main {
	public static void main(String[] arg) {
		
		// Fizz = multiple of 5
		// Buzz = multiple of 7
		// FizzBuzz = multiple of both
		
		for(int i = 1; i < 100; i++) {
			if(i % 5 == 0 && i % 7 == 0)
				System.out.println("FizzBuzz");
			else if(i % 5 == 0)
				System.out.println("Fizz");
			else if(i % 7 == 0)
				System.out.println("Buzz");
			else
				System.out.println(i);
		}
	}
}

if-else

public class main {
	public static void main(String[] arg) {
		
		// Fizz = multiple of 5
		// Buzz = multiple of 7
		// FizzBuzz = multiple of both
		
		for(int i = 1; i <= 100; i++) {
			String str = (i % 5 == 0 ? (i % 7 == 0 ? "FizzBuzz" : "Fizz") : (i % 7 == 0 ? "Buzz" : String.valueOf(i)));
			
			System.out.println(str);
		}
	}
}

What is the FizzBuzz problem in Java? 

The FizzBuzz problem tests basic Java skills by printing "Fizz" for multiples of 3, "Buzz" for 5, and "FizzBuzz" for both.