>The **`BigInteger` class** in Java handles calculations with big integral values that are beyond the limits of the primitive integer type.

The **`intValueExact()` method** of the `BigInteger` class converts the value of the `BigInteger` to an `int` value. If the value of this `BigInteger` is larger than the maximum value of an `int` type, it throws an `ArithmeticException`.

#    
## Syntax

```java
public int intValueExact()
```
## Parameter
This method doesn't take any arguments.

## Return value
This method returns the `BigInteger` value as an `int` value.

## Code 
The code below demonstrates how to use the `intValueExact` method.

import java.math.BigInteger;

class IntValueExact {
    public static void main( String args[] ) {
        BigInteger val1 = new BigInteger("10");
        BigInteger val2 = new BigInteger("2147483648");
        System.out.println("IntValueExact of " + val1 + "  : "+ val1.intValueExact());
        try{
          System.out.println("IntValueExact of " + val2 + "  : "+ val2.intValueExact());
        } catch(Exception e) {
          System.out.println("Exception while converting the " + val2 + " - \n" + e);
        }
        
    }
}

## Explanation

In the above code, we do the following: 

- **Lines 5-6**: We create two `BigInteger`objects: `val1` with value `10`, and  `val2` with the value `2147483648`.

* **Line 7**: We call the `intValueExact` method of the `val1` object. This returns the  `BigInteger` value as  `int`. The value `10` can be stored in `int`, so there is no exception. 

* **Line 9**: We call the `intValueExact` method of the `val2` object. The value `2147483648` is too large to be stored in `int`, so an `ArithmeticException` is thrown.

What is the BigInteger.intValueExact() method in Java?

Converts BigInteger to int, throwing an ArithmeticException for values exceeding int's range.