The numberOfLeadingZeros() method of the Integer class is a static method used to get the total number of zero bits preceding the
Let’s understand this method with the help of examples.
123123: 1111011The highest one bit of the 123 in its binary representation is at position 7, i.e., the leftmost one-bit.
Now, the number of leading zeros can be calculated using the formula below.
number-of-leading-zeros = 32
This is the index of the leftmost one-bit.
The number of leading zeros for 123 is 32 - 7 = 25.
1212: 1100The highest one bit of the 12 in its binary representation is at position 4, i.e., the leftmost one-bit.
Now, the number of leading zeros can be calculated using the formula below.
number-of-leading-zeros = 32
This is the index of the leftmost one-bit.
The number of leading zeros for 12 is 32 - 4 = 28.
public static int numberOfLeadingZeros(int i)
int i: The integer value whose number of leading zeros is to be computed.32-bit representation of the integer.If there are no one-bits in the binary representation of the integer value, then this method returns
32.
public class Main{private static void numberOfLeadingZeros(int number){System.out.println("Binary Representation of " + number + " - " + Integer.toBinaryString(number));System.out.println("Number of Leading Zeros of " + number + " - "+ Integer.numberOfLeadingZeros(number));}public static void main(String[] args){numberOfLeadingZeros(123);System.out.println("----------");numberOfLeadingZeros(0);System.out.println("----------");numberOfLeadingZeros(12);}}