The **`DAYOFYEAR()`** function returns the day of the year from a date sent as a parameter. There are 365 days in a year. 

>There are 366 days in a leap year.

Figure 1 shows a visual representation of the `DAYOFYEAR()` function.

# Syntax
```sql
DAYOFYEAR(date)
```
# Parameter
The `DAYOFYEAR()` function takes the date as a parameter.
> Dates must be in the format YYYY-MM-DD, or else this function returns `NULL`. 

# Return value
The `DAYOFYEAR()` function returns the day of the year from a date sent as a parameter.  
>It returns `NULL` if the date is invalid.


# Example





-- current date  
SELECT DAYOFYEAR(NOW());

-- invalid month
SELECT DAYOFYEAR('2021-13-12');

-- valid month/day
SELECT DAYOFYEAR('2021-05-03');

-- invalid day
SELECT DAYOFYEAR('2021-2-30');

<h2>Syntax</h2>
```sql
DAYOFYEAR(date)
```
<h2>Parameter</h2>
The `DAYOFYEAR()` function takes the date as a parameter.
> Dates must be in the format YYYY-MM-DD, or else this function returns `NULL`. 
<h2>Return value</h2>
The `DAYOFYEAR()` function returns the day of the year from a date sent as a parameter.  
>It returns `NULL` if the date is invalid.
<h2>Example</h2>





What is DAYOFYEAR() in SQL?

The DAYOFYEAR() function returns the day number of the year from a given date in YYYY-MM-DD format.