To remove the entries of `LinkedHashMap` that match a specific condition we:
* Get the entries of the `LinkedHashMap`.
* Use the `removeAll` method to remove all the entries that match a specific condition.




fun main() {
  //create a new LinkedHashMap which can have integer type as key, and string type as value
  val map: LinkedHashMap<Int, String> = linkedMapOf()
  map.put(1, "one")
  map.put(2, "two")
  map.put(3, "three")
  map.put(4, "four")
  println("The map is : $map")
  // get all entries of the map
  val entries = map.entries;
  // remove all entries with even value as keys
  entries.removeAll{ (key, _) -> key % 2 == 0 }
  println("\nAfter removing the entries with even keys. \nThe map is : $map")
}

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## Explanation


* **Line 3**: We create a new `LinkedHashMap` object named `map`. We use the `linkedMapOf` method to create an empty `LinkedHashMap`.
* **Lines 4 - 7**: We add four new entries, `{1=one, 2=two,3=three, 4=four}`, to the `map` using the `put()` method.
* **Line 10**: We access the `entries` property of the `map` to get the map's entries (key-value pair). The `entries` properties return the map's keys as a `MutableSet`.
* **Line 12**: We use the `removeAll` method on the returned `entries` to remove all the entries with an even value as a key. In our case, the mapping for key 2,4 is removed. After calling this method, the map is `{1=one,3=three}`.

Remove LinkedHashMap entries that match test conditions in Kotlin

Explanation