To remove the entries of LinkedHashMap that match a specific condition we:
LinkedHashMap.removeAll method to remove all the entries that match a specific condition.fun main() {//create a new LinkedHashMap which can have integer type as key, and string type as valueval map: LinkedHashMap<Int, String> = linkedMapOf()map.put(1, "one")map.put(2, "two")map.put(3, "three")map.put(4, "four")println("The map is : $map")// get all entries of the mapval entries = map.entries;// remove all entries with even value as keysentries.removeAll{ (key, _) -> key % 2 == 0 }println("\nAfter removing the entries with even keys. \nThe map is : $map")}
LinkedHashMap object named map. We use the linkedMapOf method to create an empty LinkedHashMap.{1=one, 2=two,3=three, 4=four}, to the map using the put() method.entries property of the map to get the map’s entries (key-value pair). The entries properties return the map’s keys as a MutableSet.removeAll method on the returned entries to remove all the entries with an even value as a key. In our case, the mapping for key 2,4 is removed. After calling this method, the map is {1=one,3=three}.