The removeAt() method removes an element at the given index.
An
is a resizable array that allows us to add or remove an element from both the front and back. ArrayDeque Array Double Ended Queue
fun removeAt(index: Int): E
This method takes the index of the element to be removed from the ArrayDeque.
The
IndexOutOfBoundExceptionis thrown if the index value is greater than or equal to the size of thedeque.
This method returns the element removed from the deque.
The example below demonstrates how to use the removeAt() method to remove an element at the specific index of the deque.
fun main() {// create a new deque which can have string elementsvar deque = ArrayDeque<String>()// add three elements to dequeudeque.add("one");deque.add("two");deque.add("three");println("The deque is " + deque);// remove elements at index 0println("\ndeque.removeAt(0) :" + deque.removeAt(0));println("The deque is $deque \n");try {// index 4 is greater than the size of the dequeprintln("\ndeque.removeAt(4) :" + deque.removeAt(4));} catch (e:Exception) {println(e)}}
Line 3: We create an ArrayDeque with the name deque.
Lines 6-8: We use the add method to add three elements to deque. Now deque is {one, two, three}.
Line 13: We use the removeAt() method with 0 as an argument. This will remove the element at index 0 and return the removed element. We will get one as the return value. Now deque is {two, three}.
Line 18: We use the removeAt() method with 4 as an argument. The deque contains only two elements. When we try to access the index which is greater than or equal to the size of deque, we get IndexOutOfBoundsException.