How to swap nodes in a linked list

class Node:
  # Creating a node
  def __init__(self, data):
    self.data = data
    self.next = None

class LinkedList:
  def __init__(self):
    self.head = None 

  def searchNodes(self, x, y):
    currentX = currentY = self.head
    prevX = prevY = None
        
    # search for x 
    while currentX.data != x and currentX != None:
      prevX = currentX
      currentX = currentX.next

    # search for y
    while currentY.data != y and currentY != None:
      prevY = currentY 
      currentY = currentY.next
              
    return prevX, currentX, prevY, currentY, 

  def swap(self, x, y):
    # both keys are same or null, do nothing
    if x == y:
        return
    
    prevX, currentX, prevY, currentY = self.searchNodes(x, y)
    
    if currentX is None and currentY is None:
      return

    # x is not head
    if  prevX is not None:
        prevX.next = currentY  
    else:
        # make y as head
        self.head = currentY
    
    # y is not head
    if  prevY is not None:
        prevY.next = currentX  
    else:
        # make x as head
        self.head = currentX 
    
    # swap remaining pointers    
    temp = currentX.next
    currentX.next = currentY.next
    currentY.next = temp  
  
  def push(self, new_data):
    new_node = Node(new_data)
    new_node.next = self.head
    self.head = new_node
 
  def printLinkedList(self):
    temp = self.head
    while temp != None:
      print(temp.data, end=" -> ")
      temp = temp.next
      
if __name__ == '__main__':
  linked_list = LinkedList()

  # Assign data values
  linked_list.push(5)
  linked_list.push(4)
  linked_list.push(3)
  linked_list.push(2)
  linked_list.push(1) 
  # Print the linked list data
  print('Before Swap: ')
  linked_list.printLinkedList()
  
  linked_list.swap(1, 3)
  
  # Print the linked list data
  print('\nAfter Swap: ')
  linked_list.printLinkedList()