This shot will discuss how to make a right arrow pattern in `C++` using stars (`*`).

# Approach

We will use nested loops to generate this pattern. A **nested loop** is an *outer* loop that contains an *inner* loop.

Let’s look at the image below to understand this better.

To generate the above pattern, we have to use a nested `for` loop to first `print` the center horizontal line. Then, the upper right and bottom right diagonal lines  complete the figure.

# Code

Let’s look at the below code snippet to understand it better.

#include <iostream>
using namespace std;

int main() {
  int number;
  cin >> number;
  
  // right arrow
  for (int i = 0; i <= number; i++) {
    for (int j = 0; j < number; j++) {
      if (i == number/2 || j - i == number/2 || i + j == number/2 *3)
        cout << "*";
      else 
        cout << " ";
    }
    cout << endl;
  }
  
  return 0;
}

# Explanation

>To run the code, enter any whole number in the input box.

* In line 5, we initialize the variable `number`.

* In line 6, we take the input as a `number` using `cin >>`.

* In line 9, we initialize an *outer* `for` loop where we give conditions to run the loop `number` times.

* From lines 10 to 14, we initialize an *inner* `for` loop, where we give conditions to run the loop `number` times to print the center horizontal line, upper right diagonal, and bottom-right diagonal to generate a right arrow pattern.

* In line 16, we print a next line character to print the `*` or `( )` from the next line onwards.

In this way, we have learned to generate a right arrow pattern using stars in C++.


How to make a right arrow pattern using stars in C++

Nested loops in C++ generate a right arrow pattern with stars, iterating for center, upper, and lower lines.