How to catch an exception caused by 0 as a divisor in Java

Overview

We can use the try/catch exception handling to catch the exception if a divisor is 0 in Java. When a particular number value is divided by 0, an exception called ArithmeticException is thrown.

Syntax

try{
    numbervaleu / 0; // number value divide by 0
}
catch (ArithmeticException e) // catch the error
{
    System.out.println(e)
}
Syntax for try/catch for ArithmeticException error

Example 1

class HelloWorld {
    public static void main( String args[] ) {
      // create a number value
      int numValue = 100;
      // divide by 0 and print value
      System.out.println(numValue/0);
    }
}

Explanation 1

In the code above:

  • Line 5: We create a number value.
  • Line 8: We divide the number value by 0 and print the result.

The code above throws an error. Let's handle this error below:

Example 2

class HelloWorld {
    public static void main( String args[] ) {
      try{
        // create a number value
        int numValue = 100;
        // divide by 0 and print value
        System.out.println(numValue/0);
      }      
      catch(ArithmeticException e)
      {
        System.out.println("The error is :" +  e);
      }
    }
}

Explanation 2

In the code above:

  • Line 3: We use the try/catch exception handling to catch the error.
  • Line 10: We specify that the error to catch is any error or exception called ArithmeticException.
  • Line 12: We print the error to the console.

Free AI Mock Interviews
Coding Interview
Coding PatternsFree Interview
Gain insights and practical experience with coding patterns through targeted MCQs and coding problems, designed to match and challenge your expertise level.
System Design
You TubeFree Interview
Learn to design a video streaming platform like YouTube by tackling functional and non-functional requirements, core components, and high-level to detailed design challenges.

Free Resources

License: Creative Commons-Attribution-ShareAlike 4.0 (CC-BY-SA 4.0)