The built-in **```intersection_update()```** method in Python is used to update a set that is calling the method with the elements it has in common with another set.

Figure 1 uses a Venn diagram to represent the *intersection* of two sets.

<h2>Syntax</h2>

```python
x.intersection_update(y)
```
<h2>Parameters and return value</h3>

The ```intersection_update()``` method requires at least one set to be passed as a parameter. However, it is up to the user to choose how many sets to compare. 

In addition, it is important to take note of the fact that this method returns ```None```, and the set that calls the method is simply updated. 

#Passing two sets as parameters

x = {'Red', 'Blue', 'Purple', 'Orange'}
y = {'Yellow', 'Orange', 'Blue', 'Turquoise'}

x.intersection_update(y)
print(x)

#Passing more than two sets as parameters

x = {'Red', 'Blue', 'Purple', 'Orange'}
y = {'Yellow', 'Orange', 'Blue', 'Turquoise'}
z = {'Cyan', 'Pink', 'Blue', 'Lavender', 'Orange'}

x.intersection_update(y,z)
print(x)

How does set intersection_update() work in Python?

Syntax

Parameters and return value

Example #1

Example #2