#   
## Problem
Write a program that prints numbers from `1 to 100`, and:
 
* For multiples of `3`, print `Fizz` instead of the number. 
* For multiples of `5`, print `Buzz`. 
* For multiples of `3` and `5`, print `FizzBuzz`. 
* For others, print `number`.

## Example
### Input

`1,2,3,4,5... 100`

### Output

1, 2, `Fizz`, 4, `Buzz`, `Fizz`, 7, 8, `Fizz`, `Buzz`, 11, `Fizz`, 13, 14, 
`FizzBuzz`...

### Explanation

* `1` and `2` are not multiples of either `3` or `5`, so we print the same number.

* `3` is a multiple of `3`, so we print `Fizz`.
* `5` is a multiple of `5`, so we print `Buzz`.
* `6` is a multiple of `3`, so we print `Fizz`.
* `7` and `8` are not multiples of either `3` or `5`, so we print the same number.
* `9` is a multiple of `3`, so we print `Fizz`.
* `10` is a multiple of `5`, so we print `Fizz`.
* `11` is not a multiple of either `3` or `5`, so we print the same number.
* `12` is a multiple of `3`, so we print `Fizz`.
* `13` and `14` are not multiples of either `3` or `5`, so we print the same number.
* `15` is a multiple of both `3` and `5`, so we print `FizzBuzz`.



#    
## Implementation in Python
We will use a `for-in-range` loop to solve this problem.

In the code snippet below, we use a `for-in-range` loop to traverse numbers from `1` to `100`.

>Note that we use `101`; the loop won't include last element, so it goes up to `100`.

Use `if-elif-else` to check if the number is divisible by `3` or `5` or both.
* Check with both the numbers and then check for the numbers individually, as shown in the code below.
* If the number is not divisible by neither `3` nor `5`, then print the same number.

#for loop that traverses numbers from 1 to 100
for i in range(1,101):
  #check if number is divisible by both 3 and 5
  if(i%3==0 and i%5==0):
    print("FizzBuzz")
  #check if number is divisible by 3
  elif(i%3 == 0):
    print("Fizz")
  #check if number is divisible by 5
  elif(i%5 == 0):
    print("Buzz")
  #if not divisible by either of them print the i
  else:
    print(i)

Fizz Buzz implementation in Python

Print numbers 1-100, replacing multiples of 3 with Fizz, 5 with Buzz, and both with FizzBuzz. Use for-in-range and if-elif-else in Python.