#     
## Overview
We use the **`last(where:)` method** to get the last element of an array that satisfies a given condition.

## Syntax
```swift
arr.last(where: condition)
```
## Parameters
**`arr`**: This is the array for which we want to find the last element, in order to satisfy a given condition.

Condition: 
This closure takes an array element as its argument and returns a `Boolean` value, indicating whether the element matches the condition.
## Return value
What is returned is the last element of the array that satisfies the condition. Otherwise, nothing is returned if there is no element that satisfies the condition.
## Code


let evenNumbers = [2, 4, 6, 8, 10]
let twoLetterWords = ["up", "go", "me", "we"] 
let numbers = [2, 3, -4, 5, -9]

// invoke the last(where:) method
let lastGreaterThanFive = evenNumbers.last(where: {$0 >= 5})!
let lastTwoLetters = twoLetterWords.last(where: {$0.count == 2})!
let lastNegative = numbers.last(where: {$0 < 0})!

// print results
print(lastGreaterThanFive)
print(lastTwoLetters)
print(lastNegative)

## Explanation
* Lines 1-3: We create three arrays.
* Lines 6-8: We invoke the `last(where:)` method on the arrays we created and store the returned results in some variables.
* Lines 11-13: We print the results.

Fetching the last element to satisfy a condition in Swift arrays

Overview

Syntax

Parameters

Return value

Code

Explanation